cos(x+45°) + cos(x - 45°) = square root of 2
Mathematics, 07.04.2020 04:46 Wolfy07
Solve each equation for 0° < x < 360°.
cos(x+45°) + cos(x - 45°) = square root of 2
a. 45
b. 10
c.0
d.90
Answers: 1
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Solve each equation for 0° < x < 360°.
cos(x+45°) + cos(x - 45°) = square root of 2
cos(x+45°) + cos(x - 45°) = square root of 2
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