For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent confidence, assuming a population standard deviation of $7,500 (same as last year).

Required: (Round your answers UP to the nearest integer.)

(a) E = $2,000

Sample size
(b) E = $1,000

Sample size
(c) E = $500

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation = $7,500

= 1 - confidence interval = 1 - .95 = .05

=   = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  =

                           E   =

Squaring both side

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     =

         1000   =  

Squaring both side

n = 216

(c)   Margin of error ( E) = $500

   E =

  500 =

Squaring both side

n = 864

idk

step-by-step explanation: