What are the potential solutions to the equation below?
2in(x+3)= 0
O X=-3 and x=-4
Ox=-2 and x=-4
OX= 2 and X=-3
OX= 2 and x=4

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

nada

step-by-step explanation: