PLEASE HELP! Find the side of a square whose diagonal is of the given measure. Given = 15sqrt2 cm.

15 units

Step-by-step explanation:

  15 units .

In this case, a square, the two sides of the square (forming a right triangle) are equal), and the "diagonal" forming is the hypotenuse of the right triangle.

In these cases, the measurements of the angles of the right triangle are "45, 45, 90" ; and the measurements of the sides are:  "a, a, a√2" ; in which "a√2" is the hypotenuse.

We are given:  "15√2" is the hypotenuse" ; and we are given that this is a right triangle of a square with a diagonal length (i.e. "hypotenuse" of "15√2" ; so the measure of the side of the "square" (and other two sides of the triangle formed) is:  15 units.  

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation: