Y" = F(x, y′) by letting v = y′, v′ = y″ and arriving at a first-order equation of the form v′ = F(x, v). If this new equation in v can be solved, it is then possible to find y by integrating dy/dx = v(x). xy''+y'=x

The solution to the differential

xy'' + y' = x

is

y = x + C1 lnx + C2

Step-by-step explanation:

Given the differential equation:

xy'' + y' = x (1)

Let us use the substitution:

y' = v, and y'' = v'

Then (1) becomes

xv' + v = x

Or

xdv/dx + v = x

This is a first order differential equation, that can be rewritten as:

d(xv) = d(1)

because

xdv/dx + v = x

Multiplying both sides by dx, we have

xdv + vdx = xdx

From the product rule of differentiation,

d(xv) = dv + vdx

Using this, we have

d(xv) = dx

Integrating both sides with respect to x, we have

xv = x + C1

Dividing both sides by x, we have

v = 1 + C1/x

But v = y'

y' = 1 + C1/x

Integrating both sides with respect to x, we have

y = x + C1 lnx + C2

step-by-step explanation:

if x = 2 you have to find x to finish the problem

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: