Please help :(

Ian and Danny work for a construction company. The table shows their daily wages (in dollars) for a week picked randomly from the calendar year.

Ian’s Wages ($) Danny’s Wages ($)
96 153
120 89
114 91
111 96
106 129
123 94
110 99

The best way to compare Ian’s and Danny's wages is by using the (mean, median, mean absolute deviation, interquartile range) as the measure of center.

Comparing this measure of center of the two data sets indicates that (Ian, Danny) generally earned higher wages during the days listed.

6 meters

step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

answer: the answer is 110