Mathematics, 20.09.2019 06:00 DaylaReevaFEEVA5040

Acopper pipe, used for plumbing from the water main to a house, is 4 meters long and has a circular cross-section 2.8 cm in diameter.
there is a 2 cm diameter hole in the center of the cross-section for the entire length of the rod. what is the volume of copper in the rod in cubic inches?
the density of copper is 559lb_m/ft^3 . what is the mass of the copper pipe in pounds?
what is the volume of copper in cubic inches?

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The volume of the hose is equal to the difference of the areas of the inner and outer circles with area equal to pi d^2 / 4 multiplied by height of hose, 4 meters. The annulus area is equal to 3.02 cm2.The volume is equal to 0.0012 cub, m .mass is 0.0012 cub, m times density. answer is 0.67 ft3.

Answer from: Quest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.