Give the equation of the circle centered at the origin and passing through the point (0, -11).

answer

x^2 + y^2 = 121

set up equation

the equation of a circle is (x - h)^2 + (y - k)^2 = r^2

where h is the center x coordinate and k is the center y coordinate

values

from the origin (0, 0) we know that h = 0 and k = 0

since the circle passes through (0, -11) the distance from the origin is 11

r =11

r^2 = 121

plug in values

now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2

(x - h)^2 + (y - k)^2 = r^2

(x - 0)^2 + (y - 0)^2 = 121

x^2 + y^2 = 121

a net is a diagram that shows a “flattened” view of a solid. in a net, each face and base is shown with all of its dimensions. a net can also serve as a pattern to build a three-dimensional solid.

a pyramid is a three-dimensional object with a base that is a polygon and triangular faces that meet at one vertex.

" the net of a triangular pyramid consists of four triangles. the base here we are given of the pyramid is a equilateral   triangle, and the lateral faces are also triangles "

m a t h w a y. c o m

step-by-step explanation: