PART I:
You need 1045 mL of a 70% alcohol solution. On hand, you have a 5% alcohol mixture. How much of the 5% alcohol mixture and pure alcohol will you need to obtain the desired solution?

PART II:
You need a 85% alcohol solution. On hand, you have a 595 mL of a 95% alcohol mixture. How much pure water will you need to add to obtain the desired solution?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.