Approximate to three decimal places using Newton's Method of 3^(-1/4)
and be sure to include the setup with the recursive formula.

Step-by-step explanation:

Newton's method seeks a solution to the equation f(x) = 0. The value we seek will be a solution to ...

  x = 3^(-1/4)

We can rearrange this to put it into an appropriate form.

  x^4 = 3^-1 . . . . . . take 4th powers

  3x^4 = 1 . . . . . . . .multiply by 3

  3x^4 -1 = 0 . . . . . subtract the right side to make a polynomial in standard form

So, the function we want to find a zero of can be ...

  f(x) = 3x^4 -1

The Newton's method iterator for this will be ...

In the attachment, we have defined the iteration function to be g(x). The graph shows us a starting value: .

Then the first iteration will give accuracy to 3 decimal places*:

  x ≈ (9·0.76^4 +1)/(12·0.76^3) = 4.00259584/5.267712 ≈ 0.7598357

The approximate result is x = 0.760.

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* The value shown here is actually accurate to 7 decimal places. One more iteration gets accuracy to the full precision of the calculator display.

true

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x