Mathematics, 04.04.2020 22:50 zzzio1866

Solve the equation for x 2(x-4)=4x+3x+6

Answers: 1

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Answer from: coco8560

-14/5 =x

Step-by-step explanation:

2(x-4)=4x+3x+6

Distribute

2x -8 = 4x+3x +6

Combine like terms

2x-8 = 7x+6

Subtract 2x from each side

2x-2x-8 = 7x-2x+6

-8 = 5x+6

Subtract 6 from each side

-8-6 = 5x+6-6

-14 = 5x

Divide each side by 5

-14/5 = 5x/5

-14/5 =x

Answer from: bicaplinger7766

x = $\frac{-14}{5}$

Step-by-step explanation:

2(x-4)=4x+3x+6

Multiply

2x - 8 = 4x + 3x + 6

Add

2x - 8 = 7x + 6

Add 8 to both sides

2x = 7x + 14

Subtract 7x from both sides

-5x = 14

Simplify

5x = -14

Divide by -5

x = $\frac{-14}{5}$

Hope this was useful to you!

Answer from: Quest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

Answer from: Quest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

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