When 3g ^2- 4g+ 2 is subtracted from 7g^2+ 5g- 1, the difference is

  4g^2 +9g -3

Step-by-step explanation:

(7g^2+ 5g- 1) -(3g ^2- 4g+ 2)

= 7g^2 +5g -1 -3g^2 +4g -2 . . . . . distribute the minus sign

= g^2(7 -3) +g(5 +4) +(-1 -2) . . . . . add like terms

= 4g^2 +9g -3

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

1) is right

step-by-step explanation: