Write v = 2x2 + 12x +1 in vertex form.
A. y = (x+3)2 - 17
B. y = (x+4)
C. y=2(x+3)2 – 17
D. y = 2(x + 2)2 + 12

C

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)²  + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 12x + 1

To express in vertex form use the method of completing the square.

The coefficient of the x² term must be 1 , thus factor out 2 from 2x² + 12x

y = 2(x² + 6x) + 1

add/ subtract ( half the coefficient of the x- term)² to x² + 6x

y = 2(x² + 2(3)x + 9 - 9) + 1

  = 2(x + 3)² - 18 + 1

  = 2(x + 3)² - 17 → C

answer : C    2(x-3)²-17

Step-by-step explanation:

hello :

answer : C    2(x-3)²-17

calculate :   2(x-3)²-17 = 2(x²-6x+9)-17 = 2x²-12x+18-17

                  2(x-3)²-17 = 2x²-12x+1(right)

the least common denominator is 40