Factor. 3ab-6b^2-2bc+ac

(Thank you, please explain all steps)

(3b + c)(a - 2b)

Step-by-step explanation:

Given

3ab - 6b² - 2bc + ac ← Rearranging

= 3ab + ac - 6b² - 2bc (factor the first/second and third/fourth terms )

= a(3b + c) - 2b(3b + c) ← factor out (3b + c) from each term

= (3b + c)(a - 2b)

(a-2b)(3b-c)

Step-by-step explanation:

3ab-6b^2-2bc+ac

Let's rearrange

3ab+ac-6b^2-2bc

Let's factorise

a(3b+c)-2b(3b+c)

(a-2b)(3b+c)

Since the answer cannot be solved further

The answer is (a-2b)(3b+c)

step-by-step explanation: