The function f(x)f(x) is a quartic function and the zeros of f(x)f(x) are -6−6, -5−5, -2−2 and 11. Assume the leading coefficient of f(x)f(x) is 11. Write the equation of the quartic polynomial in standard form.

A quartic function is a function given by the the following equation in standard form:

From the statement we must assume the leading coefficient of f(x) is 11, so:

The zeros are:

So, we can write:

Finally:

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.