A square in a rectangle have the same perimeter. The length of a side of the square is 4x-1. The length of the rectangle is 2x+2 and the width is 2x

The value x is 1, if the perimeter of square and rectangle are same. The perimeter of square and rectangle is 12 units.

Step-by-step explanation:

The given is,

                A square in a rectangle have the same perimeter

                The length of a side of the square is 4x-1

                The length of the rectangle is 2x+2 and width is 2x

Step:1

                Let, a - Side of square

                        l - Length of the rectangle

                       w - Width of the rectangle

Step:2

                Formula for perimeter of square is,

                                    .............................(1)

                Formula for perimeter of rectangle is,

                                   ....................(2)

Step:3

                From given,

                            Equation (1) = Equation (2)

               where,

                         a = 4x-1

                          l = 2x+2

                         w = 2x

               Substitute the values,

                       4 ( 4x-1 ) = 2 ( 2x+2+2x )

                            16x - 4 = 2 (4x + 2)

                            16x - 4 = 8x + 4

                          16x - 8x = 8                      

                                   8x = 8

                                     x = 1

Step:4

         Substitute the values of x,

                   a = 4(1)-1 = 3

                     l = 2(1)+2) = 4

                   w = 2(1) = 2

          Perimeter of square and rectangle is 12 units

Result:

           The value x is 1, if the perimeter of square and rectangle are same. The perimeter of square and rectangle is 12 units.

y=mx+b is the final answer!   : )

5050 i think

step-by-step explanation: