The mean potassium content of a popular sports drink is listed as 138 mg in a 32-oz bottle. Analysis of 40 bottles indicates a sample mean of 136.9 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.

The value for p <0.1  i.e. 0.02088 that means ,we had success in test on potassium content

Step-by-step explanation:

Given:

Means: 138 mg

sample size =40

New mean=136.9 mg

To find : Hypothesis on test.

Solution:

We know that ,

Z=(X-mean)/standard deviation)/{(sqrt(sample size)}

Consider the standard deviation of 3.00 mg

Z=(136.9-138)/(3/sqrt(40))

=-1.1/0.4743

Z=-2.3192

two tailed test

=2{(1-p(<z))}

P value for Z=2.3192 is 0.98956

=2{1-0.98956}

=0.02088

The value for p <0.1

we had success in test on potassium content.

answer: options?

step-by-step explanation:

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