Mathematics, 04.04.2020 10:57 xo216aaliyah216xo
The architect stands 6 feet from a climbing frame, looking up at the top of the frame at an angle of 63.43°. It is 5 and a half feet from ground to the architect’s eyes. The vertical distance from eye level to the top of the climbing frame is feet. The height of the entire climbing frame is feet.
Answers: 2
Mathematics, 21.06.2019 13:00, lamwil9432
20 points! asap! a is known to be 6,500 feet above sea level; ab = 600 feet. the angle at a looking up at p is 20°. the angle at b looking up at p is 35°. how far above sea level is the peak p? find the height of the mountain peak to the nearest foot. height above sea level =
Answers: 1
Mathematics, 21.06.2019 20:00, paulesparsa6
Given the two similar triangles, how do i find the missing length? if a=4, b=5, and b'=7.5 find a'
Answers: 1
Mathematics, 22.06.2019 01:10, tashatyron24pejls0
|z| > (1/2) {-1/2, 1/2} {z|(-1/2) < z < (1/2)} {z|z < (-1/2) ∪ z > (1/2)}
Answers: 3
Mathematics, 22.06.2019 02:00, Kemosdasavage
What is solution for the following system of equations, 2x+8y=4 and x=-3y+5 1) x=14 y=-3 2) x=2 y=-3 3) x=-3 y=-3 4)x=12 y=5
Answers: 1
The architect stands 6 feet from a climbing frame, looking up at the top of the frame at an angle of...
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