How do you write the equation of a circle with the center (6,2) and radius r=8?

(x-6)^2 + (y-2)^2 = 64

Step-by-step explanation:

We can write the equation of circle as

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-6)^2 + (y-2)^2 = 8^2

(x-6)^2 + (y-2)^2 = 64

Circle equation: (x - h)² + (y - k)² = r²

The center is (h, k) and the radius is r.

(x - 6)² + (y - 2)² = 8²

(x - 6)² + (y - 2)² = 64

Best of Luck!

abde or 1,2,4, 5 is the answer

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3