Incredibly, Enzo wins 555 tickets from every game, and Beatriz wins 111111 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets. What is the minimum number of games that Enzo could have played

55 games.

Step-by-step explanation:

We have been given that Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets. We are asked to find the minimum number of games that Enzo could have played.

To solve our given problem, we need to find least common multiple of 1 and 55.

We know that least common multiple of two numbers is smallest umber, which is divisible by both numbers.

We know that 5 and 11 are prime numbers, so there LCM would be product of both numbers.

Therefore, Enzo could have played 55 games at least.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

24

step-by-step explanation: