Flying with the wind a plane went 383 mph. Flying into the same wind the plane only went 319 mph. Find the speed of the wind and the speed of the plane in still air.

The speed of the wind is 32 mph and the speed of the plane in still air is 351 mph.

Step-by-step explanation:

Let the speed of the plane be Vp and the speed of the wind be Vw. In the first situation, the wind is exerting force towards the same direction as the plane so we can say that Vp + Vw = 383 mph. In the second situation, the forces are opposite of each other, so the equation can be written as Vp - Vw = 319 mph.

If we solve them together, we get the result of 2Vp = 702 mph which means that the speed of the plane is Vp = 351 mph. If we put Vp into one of the equations and solve for Vw then the speed of the wind can be found as       Vw = 32 mph.

I hope this answer helps.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7