At a post office, the weight of the mail at 10.00 a. M was 80 pounds. Two hours later, the weight of the mail had increased by 30%. Find the weight of the mail at noon.

The weight of mail at noon is 104 pounds.

Step-by-step explanation:

Given that , At a post office, the weight of the mail at 10.00 A.M was 80 pounds.

Two hours later, the weight of the mail had increased by 30%.

Since , time after 2 hours of 10 A.M would be 12 P.M which is known as noon.

Mathematically , the weight of the mail at noon = (Weight at 10 AM) +30% of (Weight at 10 AM)

= 80 + 0.30(80) pounds

= 80 (1+0.30) pounds

= 80 (1.30) pounds

= 104 pounds

Hence, the weight of mail at noon is 104 pounds.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value