The waiting time in line in a particular call center is normally distributed with an average of 1.7 minutes. they want to imporve thier preformance so they take a sample of the last 10 days and find that they standard deviation is 0.2 minuetes. how many minuets does the lingest of the 5% shortest calls last

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

what is the question?

step-by-step explanation:

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.

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step-by-step explanation: