A process that fills packages is stopped whenever a package is detected whose weight falls outside the specification. Assume that each package has probability 0.01 of falling outside the specification and that the weights of the packages are independent. Find the mean number of packages that will be filled before the process is stopped.

The mean number of packages that will be filled before the process is stopped  is 100

Step-by-step explanation:

Step 1

Given that each package has probability 0.01 of falling outside the specification (Probability of Failure)

The probability of Success is (100-probability of failure)=(100-0.01)=0.99

It is important to note that the weight of the packages are independent

Using the data given in the  question we get  the following:

P(fail) =Probability of Failure

P(success)=Probability of Success

P(fail) = 0.01 and P(success) = 0.99

Step 2

The mean of the Geometric distribution is:

P = 0.01;

μx = 1/p = 1/0.01 = 100

Step 3

Thus, we can say that the mean number of packages that will be filled before the process is stopped is 100

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term