A bag contains 25 cents and 50 cent coins whose total value is $30 if the number of 25 cent coins is four times that of 50 cent coins, find the number of each type coins. please may I also have the equation.

Number of 25 cents coins is  80 and number of 50 cents coins is 20.

Step-by-step explanation:

Given,

A bag contains of total value $ 30.

Number of 25 cent coins is four times that of 50 cent coins.

To find number of 25 cents coin is x

Number of 50 cents coin is y

According to the problem,

----- eq 1

x = 4y------ eq 2

Now, we will solve these two equation.

Putting the values of x = 4y in eq 1 we get,

or,  

or, = 30

or, y = 20

So, x = 4×20 = 80

Hence,

Number of 25 cents coins = 80 and number of 50 cents coins = 20

Step-by-step explanation:

Let 25 cent coin be A and 50 cent coin be B

Given

Total value of 25 cents coin and 50cents coin is $30

That’s

25A + 50B = 30

Also, 25 cents coin is equal to four times that of 50

So,

A = 4B

We now have

25A + 50B = 30

A = 4B

Substitute 4B for A into the first equation

25(4B) + 50B = 30

25 x 4B + 50B = 30

100B + 50B = 30

150B = 30

Divide both sides by 150 to isolate B

150B/150 = 30/150

B = 1/5

Recall

A = 4B

Therefore

A = 4 x 1/5

= 4/5

Number of 25 cents coin is 4/5 and that of 50 cents coin is 1/5

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841