Given the following use a Pythagorean identity to find sin(0) if 0 is in quadrant II

C.

Step-by-step explanation:

In trigonometry, we have an equation as following:

Replace θ into the above equation, we would have:

(sine θ)^2 + (cosine θ)^2 = 1

=> (sine θ)^2 = 1 - (cosine θ)^2 (1)

As given, we have cosine θ = -3/7. Replace it into the equation (1), we have:

(sine θ)^2 = 1 - (-3/7)^2

=>(sine θ)^2 = 1 - 9/49 = 40/49

=> sine θ = ± = ±

So sine θ = or  sine θ = -  

However, as θ is in quadrant II, sine θ has a positive value

=> sine θ =

So that the correct answer is C

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: