Teri begins walking at 2 miles per hour at 1:00 P. M. If Cindy leaves from the same point 30 minutes later walking at 3 miles per hour, when will she catch Teri

Therefore Cindy will catch Teri after 1 hour when she starts to walk.

Step-by-step explanation:

Assume after x hour Cindy will catch Teri.

Given that, Teri begins walking at 2 miles per hour at 1:00 pm.

Teri walks 30 minutes = 0.5 hour more than Cindy.

Teri walks (x+.5) hours.

We know that,

The distance covered by Teri in  (x+.5) hours is   miles.

The  walking speed of Cindy is 3 miles per hour.

The distance covered by Cindy in x hours is = 3x miles.

Cindy and Teri both meet at a point. So both will walk same distance.

According to the problem,

Therefore Cindy will catch Teri after 1 hour when she starts to walk.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.