Find the equation of the linear function h that has h(12)=-7 and that is perpendicular to q(a)=1/2a+38.. I don’t understand how to get the equation and how to write it into slope intercept form

Step-by-step explanation:

q(a) = ½a + 38

The slope of q is ½.  So the perpendicular slope is -1/½ = -2.

Write h(x) in point-slope form:

h − (-7) = -2 (x − 12)

h + 7 = -2 (x − 12)

Simplify to get slope-intercept form.

h + 7 = -2x + 24

h = -2x + 17

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

16 is the coefficient

hope this