Tim Murphy and Pat Donovan were engaged by the local authorities to paint the lamp-posts in a certain street. Tim, who was an early riser, arrived first on the job, and had painted three on the south side when Pat turned up and pointed out that Tim's contract was for the north side. So Tim started afresh on the north side and Pat continued on the south. When Pat had finished his side he went across the street and painted six posts for Tim, and then the job was finished. As there was an equal number of lamp-posts on each side of the street, the simple question is: Which man painted the more lamp-posts, and just how many more?

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

y=-2x0 is most likey your asnwer

there are many, many solutions to this problem.

here are 5 examples:

7555531, 7+5+5+5+5+3+1 = 31

7155553, 7+1+5+5+5+5+3 = 31

7735531, 7+7+3+5+5+3+1 = 31

7375531, 7+3+7+5+5+3+1 = 31

7335931, 7+3+3+5+9+3+1 = 31