Determine whetherf(x) = 6x2+ 12x + 8 has a minimum or maximum value and find thevalue of the minimum or maximum. Also, find the axis of symmetry

Step-by-step explanation:

A graphing calculator can answer this very quickly. The graph shows the minimum is 2, at x=-1. The axis of symmetry is the vertical line through that point so is x = -1.

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The extreme value of the quadratic ax^2 +bx +c is found at x = -b/(2a). Your quadratic has a=6 and b=12, so the extreme value is located on the line of symmetry at ...

  x = -12/(2·6)

  x = -1 . . . . . . . . . . line of symmetry; x-coordinate of vertex

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The leading coefficient of this even-degree polynomial is positive, so we know it opens upward. That means the vertex is a minimum.

The value of the function at the vertex is ...

  f(-1) = 6(-1)^2 +12(-1) +8 = 6 -12 +8 = 2

The minimum value is 2.

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

step-by-step explanation: