A fast-food chain claims one medium order of its onion rings weighs 114 grams. Patrice thinks she is getting less than what the restaurant advertises. She weighs the next 16 random orders of onion rings before she eats them and finds the sample mean is 112.4 grams and the standard deviation is 7.63 grams. What conclusion can be drawn α = 0.10?

There is not any solid evidence provided by Patrice to reject the fast food chain's claim.

Step-by-step explanation:

As Patrice weighs the next 16 random orders of onion rings before she eats them and finds the sample mean is 112.4 grams and the standard deviation is 7.63 grams so here

sample size = 16

sample mean = 112.4

standard deviation = 7.63

Formula for test statistic:

t = ( sample mean - weight ) / standard error of mean

Formula for standard error of mean:

standard error of mean =  standard deviation / sqrt (sample size)

therefore by putting the values in the above formula, we get

standard error of mean = 7.63 / sqrt(16)

Now

t = ( 112.4-114 ) / ( 7.63 / sqrt(16) )

= -0.84

p-value = P (z < -0.84) = 0.201

Therefore it fails to reject null hypothesis because p-value > 0.1

Hence, there is not any solid evidence provided by Patrice to reject the fast food chain's claim.

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5