Calculate the distance between the point c=(-8,0) and f = (-2,3) in a corrdinate plane

The squared distance is called the quadrance and it's usually the more important quantity.  But not in high school.

d² = (-2 - -8)² + (3 - 0)² = 36 + 9 = 45

d = 3√5

3√5

That's a nice exact answer so let's stop.  Depending on the question they might want a calculator approximation.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i