A truck at P, moves on a straight road, its velocity is given by v = 0.75t² - 6t + 20. When t = 6,the truck passes a breakdown car at Q. The truck then moves with a constant acceleration of 3 m/s² until the original speed is regained at point R.
(a) Find the time at R and hence distance PR.

Look, when you want to do something like put it like x^2. x2 could mean x² or x₂. so to clear confusion, know the notation. to find the product multiply the x's and you get -8x and the y's and you get 6y. since it's all being multiplied it is just -8x6y, or answer a. although the better answer is -48xy(combining -8 and 6) because you should multiply constants whenever you can.