1. Consider the quadrilateral TONE below.

Part A: Name three sets of consecutive vertices.

Part B: Name three sets of consecutive sides.

Part C: Name two sets of opposite sides.

Part D: Name three sets of adjacent angles.

Part E: Name two sets of opposite angles.

Part F: Name two diagonals.

Part A: {T,O,N}, {O,N,E}, {N,E,T}.

Part B: {TO,ON}, {ON,NE}, {NE,ET}.

Part C: {TO,NE}, {ON,ET}.

Part D: {∠ T, ∠ O}, {∠ O, ∠ N}, {∠ N, ∠ E}.

Part E: {∠ T, ∠ N}, and {∠ O, ∠ E}.

Part F: TN and OE.

Step-by-step explanation:

Considering the quadrilateral TONE,

Part A: Name of three sets of consecutive vertices are {T,O,N}, {O,N,E}, {N,E,T}.

Part B: Name of three sets of consecutive sides are {TO,ON}, {ON,NE}, {NE,ET}.

Part C: Name of two sets of opposite sides are {TO,NE}, {ON,ET}.

Part D: Name of three sets of adjacent angles are {∠ T, ∠ O}, {∠ O, ∠ N}, {∠ N, ∠ E}.

Part E: Name of two sets of opposite angles are {∠ T, ∠ N}, and {∠ O, ∠ E}.

Part F: Name of two diagonals are TN and OE. (Answer)

i used to know but i learned it a long time ago sorry

step-by-step explanation:

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.