The average response time to a bank robbery is 9 minutes. A local community wants to improve on this time, so they implement advanced training seminars. The local community predicts that the advanced training seminars will lower the average response time. They find that the new response time for a sample of 36 police officers is 8 minutes with a standard deviation of 4.2. Test whether this advanced training seminar reduced response time at a .05 level of significance.

The training does reduce response time at 0.05 level of significance

Step-by-step explanation:

Population mean for a population with normal distribution, where the standard deviation is known and the appropriate significant test is given then;

z=x-μ / δ/√n

where

μ= 9 minutes

x=8 minutes

δ= 4.2

n= 36

Applying the formula;

z= 8-9 / 4.2/√36

z= -1 / 4.2/6

z= -1 /0.7 = - 1.429

Perform the test where

H₀ : p=0.05 verse Ha : p < 0.05

Using the Z-table, find the probability that Z is less than -1.43.

You will find the probability of 0.0764 of Z being more than the value in test thus; there are high chances that results will be observed according to the null hypothesis

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )