24% of U. S. adults say they are more likely to make purchases during a sales tax holiday. you randomly select 10 adults. find the probability that the number of adults who say theu are more likely to make purchases during a sales tax holiday is (a) exactly two, (b) more than two, and (c) between two and five inclusive

a)

b) P(x>2) = 0.566

c) P(2<x<5)  = 0.334

Step-by-step explanation:

Given 24% of U.S. adults say they are more likely to make purchases during a sales tax holiday

Probability 0f U.S. adults say they are more likely to make purchases during a sales tax holiday (p) = 0.24

                            n = 10

By using Poisson distribution

mean number of make purchases during a sales tax holiday

λ = np = 10 X 0.24 = 2.4

a)

The probability of getting exactly '2'

The probability

b) The probability of getting more than '2'

              = 0.090 + 0.2177+0.261 = 0.566

P(x>2) = 0.566

c) The probability of getting between  two and five

P( 2<x<5) = P(x=3)+p(x=4) =

P(2<x<5) = 0.2090 + 0.125 = 0.334

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2