Determine the discriminant for the quadratic equation 0 = –2x2 3. based on the discriminant value, how many real number solutions does the equation have?
discriminant = b2 – 4ac

If you would like to know the discriminant of the quadratic equation 0 = -2x^2 + 3, you can do this using the following steps:

0 = -2x^2 + 3

0 = ax^2 + bx + c
a = -2, b = 0, c = 3

D = b^2 - 4 * a * c = 0^2 - 4 * (-2) * 3 = 0 + 4 * 2 * 3 = 24

The discriminant is 24 (positive).

If the discriminant of a quadratic equation is equal to zero (b^2 - 4ac = 0), there is one real root which is repeated. If the discriminant is positive (b^2 - 4ac > 0), there are two real roots; and if the discriminant is negative (b^2 - 4ac < 0), there are two complex roots.

Therefore, the equation has 2 real roots.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)