A cube-shaped satellite has side lengths of 10 centimeters. What is the least amount of aluminum needed to cover the satellite?

At least

square centimeters of aluminum is needed.

600 square centimeter.

Step-by-step explanation:

A cube-shaped satellite has side lengths of 10 centimeters.

So, the total surface area of the satellite is 2(10 × 10 + 10 × 10 + 10 × 10) = 600 sq. cm.

{The total surface area of a cuboid having length L, width W, and height H is given by 2(LW + WH + HL)}

Therefore, the least amount of aluminum needed to cover the satellite will be 600 sq. cm. (Answer)

its 4 because 2 times 2 is 4, if you double the number two you get four

my answer is$ 12

step-by-step explanation:

because 15 -2=12