A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.
Click "Show Your Work" and write a quadratic function, h(t), that shows
the height, in feet, of the soccer ball, t seconds after it was kicked. Use
the general equation h(t) = -16t2 + v0t + h0 where v0 is the initial velocity
and h0 is the initial height.

h(t) = - 16t² + 96t

Step-by-step explanation:

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

So, it initial height, ft. and initial velocity feet/sec.

Now, the quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked will be given by the general equation

⇒ h(t) = - 16t² + 96t + 0

⇒ h(t) = - 16t² + 96t (Answer)

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)