You and your friend mix water and cirtic acid. You add 3 cups of citrtic acid for every 16 cups of water Your friend adds 2 cups of citric acid for every 12 cups of water whose mixture is more acdic

A's mixture is more acidic.

Step-by-step explanation:

Given:

Two friends mix water and citric acid.

One (Let A) add 3 cups of citric acid for every 16 cups of water and another (Let B)adds 2 cups of citric acid for every 12 cups of water.

Now, we have to find that whose mixture is more acidic means:-

Solution:

A add 3 cups of citric acid for every 16 cups of water, the ratio =

B adds 2 cups of citric acid for every 12 cups of water =

Now, to find that who mix more citric acid in the mixture, firstly we will equalize the denominator of both fraction by taking LCM so that can be compare easily.

LCM of 16 and 12:- 48

16 - 16, 32, 48, 64, 80, 96....

12 - 12, 24, 36, 48, 60, 72.......

For friend A -

For friend B -

We found that in terms of 48 cups of water, friend A mixes 9 cups of acid while friend B mixes 8 cups of acid, means A is adding more acid than B and hence friend A's mixture is more acidic.

idk

step-by-step explanation:

idk

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!