What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?

1.95

Step-by-step explanation:

hello :

ln (x + 6) – ln (2x – 1) = 1  ...(*)

this expression exist : 2x-1 > 0 and x+6 > 0   means : x> 1/2 and x  > -6

hence for : x> 1/2   (*) equivalent to  ln((x+6)/(2x-1))= lne(1=lne)

(x+6)/(2x-1) = e

x+6 = e(2x-1)        means : x+6 = 2ex-e

-x+2ex = e+6

x(2e-1) = e+6

x = (e+6)/(2e-1)    =(2.73+6)/(2(2.73)-1) =8.73/4.46 =1.95

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.