Mable has 185 dollars worth of apples. Each apple is worth more then 3 dollars but less then 10 dollars. The number has four letters and in an odd number. The number is a prime number. How much is each apple worth? (REMEMBER THE NUMBER HAS TO GO INTO 185 EQUALLY)

The worth of each of Mable's apples is $5

Step-by-step explanation:

 Extracting the key information from the question:

***Mable has apples that are worth a combined 185 dollars.

*** One apple from Mable's apples worth more than three ($3) dollars but less than ten ($10) dollars.

***The cost of one apple is a number that has four letters.

*** That number (the cost) of one apple is also a prime number.

*** We are required to find or determine the worth of one of Mable's apples.

   Now, one of the clues given to us which we may use to figure out the cost or worth of one apple is that the apple is worth more than three dollars ($3) but worth less than ten dollars ($10). This means that each Mable's apple may worth $4 or $5 or $6 or $7 or $8 or $9. That is one of Mable's apples worth from $4 to $9

   Another clue to solving this puzzle is that the worth of one apple in dollars is a prime number. This implies that one of Mable's apples may worth either five dollars ($5) or seven dollars ($7).

  The next clue for unravelling this mystery is that all Mable's apples are worth a combined $185. This then means that the worth of each apple (the number) must be able to divide 185.

   Since $7 and $5 are the only two figures left standing, we will then try and see which one of them will be able to do divide the number "185".

 185/7  = 26 remainder 3

 185/5  = 37 remainder 0

 The final clue in the question is that the worth of each of Mable's apples is a figure/number that has only letters:

$7 SEVEN has = 5 letters

$5 FIVE has = 4 letters

 This now brings us to the conclusion that the worth of each of Mable's apples is five dollars ($5)  since it meets all the requirements and clues in the question.

linear pair postulates