A play court on the school playground is shaped like a square joined by a semicircle. the perimeter around the entire play court is 182.8 ft ,and 62.8 ft. of the perimeter comes from the semicircle.

Step-by-step explanation:

Perimeter of square = 182.8 ft

Perimeter of semicircle = 62.8 ft

Let teh side of the square is a and the radius of semi circle is r.

Perimeter of square = 4a

4a = 182.8

a = 45.7 ft

perimeter of semicircle = π r

π r = 62.8

r = 20 ft

Area of square part = a² = 45.7 x 45.7 = 2088.5 ft²

Area of semicircle = πr²/2 = 3.14 x 20 x 20 /2 = 628 ft²

Total area of the play court = 2088.5 + 628 = 2716.5 ft²

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!