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LLI
Female Prison Inmates Seventy-five percent of female
prison inmates are mothers. If 3 female prison inmates
are selected at random, what is the probability that none
are mothers?

Step-by-step explanation:

Let the total number of prison inmates be 100

Given that Seventy-five percent of female  prison inmates are mothers.

The number of mother inmates = 75% (100) = 75

The number of inmates who are not mothers = 100 - 75 = 25

3 female prison inmates are selected at random. The probability that none  are mothers = ??

Selecting an inmate who is not a mother = =

Selecting 3 female who are not mothers = =

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

the answer is d on edge

step-by-step explanation: