CAN YOU FIND THE PERIMETER & AREA FOR THESE QUESTIONS! FIRST COLOM IS PERIMETER SECOND ONE IS AREA !

Fig 1 : Perimeter = 30 unit and area = 40 sq unit

Fig 2 : Perimeter = 34 unit and area = 30 sq unit

Fig 3 : Perimeter = 42 unit and area = 70 sq unit

Fig 4 : Perimeter = 24 unit and area = 12 sq unit

Step-by-step explanation:

Given,

Fig 1 : Right angle triangle:

Base (b) = 10

Height (h) = 8

Hypotenuse (H) = 12

Fig: 2 Parallelogram:

Length (l) = 11

Width (b) = 6

Height (h) = 5

Fig 3 : Right angle triangle:

Base (b) = 10

Height (h) = 14

Hypotenuse (H) = 18

Fig: 4 Parallelogram:

Length (l) = 8

Width (b) = 4

Height (h) = 3

To find the area and perimeter of all the fig.

Formula:

Perimeter of right angle triangle = sum of all the sides

Area of right angle triangle =

Perimeter of parallelogram = 2(l+b)

Area of parallelogram =

Now,

Fig 1 : Right angle triangle:

Perimeter of right angle triangle = 10+12+8 = 30 unit

Area of right angle triangle = ×8×10 = 40 sq unit

Fig: 2 Parallelogram:

Perimeter of parallelogram = 2(11+6) = 34 unit

Area of parallelogram = 6×5 = 30 sq unit

Fig 3 : Right angle triangle:

Perimeter of right angle triangle = 10+14+18 = 42 unit

Area of right angle triangle = ×14×10 = 70 sq unit

Fig: 4 Parallelogram:

Perimeter of parallelogram = 2(8+4) = 24 unit

Area of parallelogram = 6×5 = 30

Area of parallelogram = 4×3 = 12 sq unit

the answer is simply just 6n add the two together as they have an n