What is the square root of 64y16

Step-by-step explanation:

The idea here is to "match" the exponent on the radicands (the number/variables under the radical sign) to the index (the little number that sits in the "arm" of the radical sign).  Your problem looks like this:

Our index is a 2.  If we could rewrite both the 64 and the y^16 with bases to the power of 2 (that's why I say to "match" the exponent to the index), we could pull out the base.  For example,

because the power is a 2 and so is the index, so we pull out the base of x.

Our rewrite would look like this:

(remember that power to power on a base means you multiply the exponents so 8 * 2 = 16).

The power on the 8 is a 2 which matches our index of 2 so we will pull out the 8; the power on the y^8 is a 2 which also matches our index of 2 so we will pull out the y^8.  The simplification of this is

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

step-by-step explanation:

659