Help me solve this algebra 2 question.

A

Step-by-step explanation:

Alright, this may come out weird on computer, but here we go.

First, you want to change this into a multiplication problem, with Keep change flip. So now it's (c^2-c-20/c^2-6c+5) * (3c-3/c^2-16). You then want to simplify some number down.

You can simplify the first part using the X game (not sure if you know this), but you put the c value at the top, and the B value at the bottom, and the two sides blank. These two values must add to equal the C value, but multiply to equal the B value, so you get -5 and 4 for the numerator of the top. Following this formula, and using difference of perfect squares, you'll end up with the following.

(c-5)(c+4)/(c-5)(c-1) * 3(c-1)/(c+4)(c-4)

You then need to cancel out your different groups, so you'll cancel out (c-5), (c+4), (c-1).

After all that, you'll end up with 3/c-4, so the answer is A.

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: