What is the solution to the equation StartFraction negative 3 d Over d squared minus 2 d minus 8 EndFraction + StartFraction 3 Over d minus 4 EndFraction = StartFraction negative 2 Over d + 2 EndFraction? d = –4 and d = 2 d = –2 and d = 4 d = 1 d = 2

d = 1

Step-by-step explanation:

-3d/(d²-2d-8) + 3/(d-4) = -2/(d+2)

d²-2d-8 = d²-4d+2d-8

= d(d-4)+2(d-4)

= (d+2)(d-4)

Since these the factors in the denominator, they can't be zero.

d cannot be 4 or -2

-3d/[(d+2)(d-4)] + 3/(d-4) = -2/(d+2)

Multiply both sides by: (d+2)(d-4)

-3d + 3(d+2) = -2(d-4)

-3d + 3d + 6 = -2d + 8

2d = 2

d = 1

The solution to the given equation is 1.

The given parameters:

The solution of the equation is calculated as follows;

The denominators are equal, so we can equate the numerators as follows;

Thus, the solution to the given equation is 1.

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