The third term in a sequence is 11.
The term-to-term rule is "take away 4".
Write an expression, in terms of n, for the nth term of the sequence.

nth term = 19 - 4(n - 1).

Step-by-step explanation:

This is an arithmetic sequence and the nth term =

a1 + d(n - 1)   where a1 = first  term and d = the common difference.

Here d = -4 and the first term ( working backwards) is  11 + 2(4) = 19.

So the answer is nth term = 19 - 4(n - 1).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.