PLEASE ASAP HELP :(
Compare Accounts A and B. Then complete the sentences.

There are two rectangles. The first rectangle with heading Account A and content principal: $16,000; annual interest: 3%, compound quarterly number of years: 10 and the second rectangle with heading Account B and content principal: $16,000; annual interest: 3%, compound monthly number of years: 10.

Account

is worth the most after 10 years. It will have a value of $

.

Account B is worth the most after 10 years. It will have a value of $21591

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

Considering account A,

P = $16000

r = 3% = 3/100 = 0.03

n = 4 because it was compounded 3 times in a year and n = 12/3 = 4

t = 10 years

Therefore,

A = 16000(1 + 0.03/4)^4 × 10

A = 16000(1 + 0.0075)^40

A = 16000(1.0075)^40

A = $21574

Considering account B,

P = $16000

r = 3% = 3/100 = 0.03

n = 12 because it was compounded 12 times in a year.

t = 10 years

Therefore,

A = 16000(1 + 0.03/12)^12 × 10

A = 16000(1 + 0.0025)^120

A = 16000(1.0025)^120

A = $21591

Therefore,

Account B is worth the most after 10 years. It will have a value of $21591

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2